2x^2-20x+96=0

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Solution for 2x^2-20x+96=0 equation: 



2x^2-20x+96=0

a = 2; b = -20; c = +96;
Δ = b2-4ac
Δ = -202-4·2·96
Δ = -368
Delta is less than zero, so there is no solution for the equation

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